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| Mad Tom |
Jun 14 2010, 05:04 PM
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#16
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Unregistered |
Some of the Op 11 ones are quite easy, others are fiendish. Try No 2, that the one I played in Leeds, its pretty straightforward. Then 4 ,5, 9 and 10, 13, 15, 16 (parody of a funeral march!), 17, 21 and 22. Then tackle the harder ones, No 3 is a good start. Then you will have learnt half of them. There is only one problem with this very logical approach. It will ber agaes before you get around to No. 11, which is by far the most beautiful of then Op. 11 Preludes. (IMNSHO!) Looks like I'll need those dice after all then! (IMG:style_emoticons/default/biggrin.gif) I ought to work out the probability of scoring 11 when rolling four dice! Anyone? (IMG:style_emoticons/default/biggrin.gif) Come on. You can work that out: a. How many ways can you add 4 numbers from the set (1,2,3,4,5,6) - duplicates permitted, to get 11. b. How many different ways can you roll each set in a. with 4 dice c. Add results from b. d. Divide by 6x6x6x6 Or (if you want even odds for each Prelude) why not use a 12 sided dice, and use a coin flip to decide whether to interpret the result as 1-12 or 13-24? Or you could use a coin and do TWO binary chops. (24 -> 12 -> 6) then use a regular cubic dice for the final selection. |
| clavicembalo |
Jun 14 2010, 05:12 PM
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#17
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Virtuoso ![]() ![]() ![]() ![]() ![]() Group: Members Posts: 3701 Joined: 21-November 09 From: Cheltenham Member No.: 81873 |
Some of the Op 11 ones are quite easy, others are fiendish. Try No 2, that the one I played in Leeds, its pretty straightforward. Then 4 ,5, 9 and 10, 13, 15, 16 (parody of a funeral march!), 17, 21 and 22. Then tackle the harder ones, No 3 is a good start. Then you will have learnt half of them. There is only one problem with this very logical approach. It will ber agaes before you get around to No. 11, which is by far the most beautiful of then Op. 11 Preludes. (IMNSHO!) Looks like I'll need those dice after all then! (IMG:style_emoticons/default/biggrin.gif) I ought to work out the probability of scoring 11 when rolling four dice! Anyone? (IMG:style_emoticons/default/biggrin.gif) Come on. You can work that out: a. How many ways can you add 4 numbers from the set (1,2,3,4,5,6) - duplicates permitted, to get 11. b. How many different ways can you roll each set in a. with 4 dice c. Add results from b. d. Divide by 6x6x6x6 Eggs ... grandmother ... I was being rhetorical MT. It's the sort of problem that sends non-mathematicians into paroxysms of fear and dread - if that's etymologically possible. However, it is slightly more involved than a two-dice problem. |
| Mad Tom |
Jun 14 2010, 10:21 PM
Post
#18
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Unregistered |
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| clavicembalo |
Jun 14 2010, 10:24 PM
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#19
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Virtuoso ![]() ![]() ![]() ![]() ![]() Group: Members Posts: 3701 Joined: 21-November 09 From: Cheltenham Member No.: 81873 |
Eggs ... grandmother ... Sorry Grandma. I was being rhetorical MT. I know. I was just being deliberately silly. By the way - I reckoned 8% (IMG:style_emoticons/default/smile.gif) |
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| Lo-Fi Version | Time is now: 20th May 2013 - 08:15 AM |